122 Best Time to Buy and Sell Stock II

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Original description:
Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (i.e., buy one and sell one share of the stock multiple times). Note: You may not engage in multiple transactions at the same time (i.e., you must sell the stock before you buy again).

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• 要求： 给一个数组，其中第i个元素表示第i天的股票价格。设计算法使得股票买卖获利最大。
  • 可以进行多次买卖
  • 再次购买以前必须卖出持有股

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• 返回： 最大收益值

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• 例子：
  • input: [7,1,5,3,6,4]
  • output: 7 第二天买，第三天卖（5-1 = 4），第四天买，第五天卖（6-3=3）==> 4+3 = 7

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Solution

由于可以进行多次买卖，只要输入序列递增，则可以进行利润累加。

class Solution(object):
    def maxProfit(self, prices):
        """
        :type prices: List[int]
        :rtype: int
        """
        if prices == [] or len(prices) == 1:
            return 0
        else:
            profit = 0
            for i in range(len(prices)-1):
                if prices[i+1] > prices[i]:
                    profit += prices[i+1]-prices[i]
            return profit
        
# with reference to :https://www.cnblogs.com/zuoyuan/p/3765980.html