237 Delete Node in a Linked List
Original Description: Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
- 要求:
给一个节点,删掉该节点。
- 返回: 无需返回
- 例子:
- input: head = [4,5,1,9], node = 5
- output: [4,1,9]
Solution
把下一个节点的指针和值都给当前节点即可。
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def deleteNode(self, node):
"""
:type node: ListNode
:rtype: void Do not return anything, modify node in-place instead.
"""
next_node = node.next
node.val = next_node.val
node.next = next_node.next